switch not getting value


Posted on 16th Feb 2014 07:03 pm by admin

what am i doing wrong?
i want to populate the country list according to the category
i want to switch in case CategoryID=1 and CatID2=2 in the country_list table

Did you know?Explore Trending and Topic pages for more stories like this.
then call on "alpha" to populate the dropdown list via ajax
the form:
Code: <!--
The following file was created by Iwo Kadziela at TECHROAM: http://www.techroam.com
This file uses MySql database and AJAX to create autopopulating dynamic select boxes.

<html>
<head>
<script src="request.js"></script>
<script type="text/javascript">

function getfirst(dd1)
{
clearSelect = document.getElementById('thirdbox');
clearSelect.options.length = 1;
//above code clears the third select box when re-clicking the first select box

var idx = dd1.selectedIndex;
var first = dd1[idx].value;
var par = document.forms["theform"];
var parelmts = par.elements;
var prezsel = parelmts["secondbox"];
if (first != "Select Something One")
{
Http.get({
url: "./alpha.php?alpha=" + first + "%",
callback: fillPrez,
cache: Http.Cache.Get
}, [prezsel]);
}
}

function getsecond(dd1)
{
var idx = dd1.selectedIndex;
var second = dd1[idx].text;
var par = document.forms["theform"];
var parelmts = par.elements;
var prezsel = parelmts["thirdbox"];
if (second != "Select Something Two")
{
Http.get({
url: "./beta.php?state=" + second,
callback: fillPrez,
cache: Http.Cache.Get
}, [prezsel]);
}
}

function fillPrez(xmlreply, prezelmt)
{
if (xmlreply.status == Http.Status.OK)
{
var prezresponse = xmlreply.responseText;
var prezar = prezresponse.split("|");
prezelmt.length = 1;
prezelmt.length = prezar.length;
for (o=1; o < prezar.length; o++)
{
prezelmt[o].text = prezar[o];
prezelmt[o].value = prezar[o];
}
}
else
{
alert("Cannot handle the AJAX call.");
}
}

function getthird(dd1,dd2) {
var idx = dd1.selectedIndex;
var third = dd1[idx].text;
if (third != "Select The Final")
{
Http.get({
url: "./final.php?state=" + dd2 + "&city=" + third,
callback: getit,
cache: Http.Cache.Get
});
}
}

function getit(xmlreply){
if (xmlreply.status == Http.Status.OK)
{
document.getElementById("final").innerHTML= xmlreply.responseText;
}
else
{
alert("Cannot handle the AJAX call.");
}
}
</script>
<style>
body {
width:800px;
margin: 0px auto;
text-align:center;
}
p {display:inline;margin:20px;}
div {clear:both;width:800px;border:1px solid #999;padding:20px;margin:20px 0px 20px 0px;}
</style>
</head>

<body>

<form name="theform">
<p>
<select name="firstbox" size="13" style="position: relative; width: 215px;" onChange="getfirst(this);">
<option value="">Select Something One</option>
<?php
do {
?>
<option value="<?php echo $row_RsCategories['CategoryID']?>"><?php echo $row_RsCategories['CategoryName']?></option>
<?php
} while ($row_RsCategories = mysql_fetch_assoc($RsCategories));
$rows = mysql_num_rows($RsCategories);
if($rows > 0) {
mysql_data_seek($RsCategories, 0);
$row_RsCategories = mysql_fetch_assoc($RsCategories);
}
?>
</select>
</p>
<p>
<select name="secondbox" size="13" style="position: relative; width: 215px;" onChange="getsecond(this);">
<option>Select Something Two</option>
</select>
</p>
<p>
<select id="thirdbox" name="thirdbox" size="13" style="position: relative; width: 215px;" onChange="getthird(this, document.theform.secondbox.options[document.theform.secondbox.selectedIndex].value);">
<option>Select The Final</option>
</select>
</p>
</form>
<center>THE FINAL CONTENT PULLED FROM DATABASE</center>
<div id="final"></div>
</body>
</html>
<?php
mysql_free_result($RsCategories);
?>

alpha.php
Code: </php
$dbconnection = mysql_connect ("localhost", "root", "") or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db ("international", $dbconnection) or die("Couldn't open database: ".mysql_error());
$alpha=$_GET['alpha'];
switch ($alpha)
{
case 1:
$result = mysql_query("SELECT CountryName from country_list WHERE CategoryID = '".$_GET['alpha']."'");
break;
case 2:
$result = mysql_query("SELECT CountryName from country_list WHERE CatID2 = '".$_GET['alpha']."'");
break;


while ($row = mysql_fetch_array($result)) {
echo "|" . $row['CountryName'];
}

?>
No comments posted yet

Your Answer:

Login to answer
97 Like 15 Dislike
Previous forums Next forums
Other forums

problem with array - multilingual page
this is my test page :
Code: <?php
if(isset($_GET['lang'])) {
if($_GET['la

Registration
ok so i have a site where people can register and login which works now thanks to someone on here th

phpMailer not working ..........
HI,
I was playing with the phpMailer script and tried to send a smiple mail using their test scri

why is it over writing
Code: $filepaths[] = $_FILES['new_image'];
foreach ($filepaths as $filepath)
{
$imagename =

Operator precedence assistance.
I did a quick Google search and couldn't quite find the answer I wanted in terms I could understand,

Login Script Issues
I am using a script I got from http://phpsense.com/php/php-login-script.html in order to allow peopl

Memory Allocation
Hi folks,
see this ex:

int v=5;
v=v+10;

then what will do the compiler before th

is_dir() problem
Hello,

I'm buidling a php scripts that dynamically get's subfolders from a specific folder.

Disabling SAP menu
How do I disable SAP menu for all the users and just restrict them to User Menu in SAP ECC 6.0?

Not loading image
When this function gets loaded it doesn't load the image just trying to figure out why.

Code:

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash