switch not getting value


Posted on 16th Feb 2014 07:03 pm by admin

what am i doing wrong?
i want to populate the country list according to the category
i want to switch in case CategoryID=1 and CatID2=2 in the country_list table

Did you know?Explore Trending and Topic pages for more stories like this.
then call on "alpha" to populate the dropdown list via ajax
the form:
Code: <!--
The following file was created by Iwo Kadziela at TECHROAM: http://www.techroam.com
This file uses MySql database and AJAX to create autopopulating dynamic select boxes.

<html>
<head>
<script src="request.js"></script>
<script type="text/javascript">

function getfirst(dd1)
{
clearSelect = document.getElementById('thirdbox');
clearSelect.options.length = 1;
//above code clears the third select box when re-clicking the first select box

var idx = dd1.selectedIndex;
var first = dd1[idx].value;
var par = document.forms["theform"];
var parelmts = par.elements;
var prezsel = parelmts["secondbox"];
if (first != "Select Something One")
{
Http.get({
url: "./alpha.php?alpha=" + first + "%",
callback: fillPrez,
cache: Http.Cache.Get
}, [prezsel]);
}
}

function getsecond(dd1)
{
var idx = dd1.selectedIndex;
var second = dd1[idx].text;
var par = document.forms["theform"];
var parelmts = par.elements;
var prezsel = parelmts["thirdbox"];
if (second != "Select Something Two")
{
Http.get({
url: "./beta.php?state=" + second,
callback: fillPrez,
cache: Http.Cache.Get
}, [prezsel]);
}
}

function fillPrez(xmlreply, prezelmt)
{
if (xmlreply.status == Http.Status.OK)
{
var prezresponse = xmlreply.responseText;
var prezar = prezresponse.split("|");
prezelmt.length = 1;
prezelmt.length = prezar.length;
for (o=1; o < prezar.length; o++)
{
prezelmt[o].text = prezar[o];
prezelmt[o].value = prezar[o];
}
}
else
{
alert("Cannot handle the AJAX call.");
}
}

function getthird(dd1,dd2) {
var idx = dd1.selectedIndex;
var third = dd1[idx].text;
if (third != "Select The Final")
{
Http.get({
url: "./final.php?state=" + dd2 + "&city=" + third,
callback: getit,
cache: Http.Cache.Get
});
}
}

function getit(xmlreply){
if (xmlreply.status == Http.Status.OK)
{
document.getElementById("final").innerHTML= xmlreply.responseText;
}
else
{
alert("Cannot handle the AJAX call.");
}
}
</script>
<style>
body {
width:800px;
margin: 0px auto;
text-align:center;
}
p {display:inline;margin:20px;}
div {clear:both;width:800px;border:1px solid #999;padding:20px;margin:20px 0px 20px 0px;}
</style>
</head>

<body>

<form name="theform">
<p>
<select name="firstbox" size="13" style="position: relative; width: 215px;" onChange="getfirst(this);">
<option value="">Select Something One</option>
<?php
do {
?>
<option value="<?php echo $row_RsCategories['CategoryID']?>"><?php echo $row_RsCategories['CategoryName']?></option>
<?php
} while ($row_RsCategories = mysql_fetch_assoc($RsCategories));
$rows = mysql_num_rows($RsCategories);
if($rows > 0) {
mysql_data_seek($RsCategories, 0);
$row_RsCategories = mysql_fetch_assoc($RsCategories);
}
?>
</select>
</p>
<p>
<select name="secondbox" size="13" style="position: relative; width: 215px;" onChange="getsecond(this);">
<option>Select Something Two</option>
</select>
</p>
<p>
<select id="thirdbox" name="thirdbox" size="13" style="position: relative; width: 215px;" onChange="getthird(this, document.theform.secondbox.options[document.theform.secondbox.selectedIndex].value);">
<option>Select The Final</option>
</select>
</p>
</form>
<center>THE FINAL CONTENT PULLED FROM DATABASE</center>
<div id="final"></div>
</body>
</html>
<?php
mysql_free_result($RsCategories);
?>

alpha.php
Code: </php
$dbconnection = mysql_connect ("localhost", "root", "") or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db ("international", $dbconnection) or die("Couldn't open database: ".mysql_error());
$alpha=$_GET['alpha'];
switch ($alpha)
{
case 1:
$result = mysql_query("SELECT CountryName from country_list WHERE CategoryID = '".$_GET['alpha']."'");
break;
case 2:
$result = mysql_query("SELECT CountryName from country_list WHERE CatID2 = '".$_GET['alpha']."'");
break;


while ($row = mysql_fetch_array($result)) {
echo "|" . $row['CountryName'];
}

?>
No comments posted yet

Your Answer:

Login to answer
97 Like 15 Dislike
Previous forums Next forums
Other forums

1,000 select boxes with 100 options?!
I have 1 drop down select box with 1,000 options.


In some case, there will be 100+ of the

How do I use ValidatorCallout extender in Login control?
Hi,I'd like to customize the look and feel of the login control a little bit. One thing I'd love to

using explode() to fill in checkboxes
Hi

I have a field stored in a table that contains regions in the UK separated by commas. Ther

Is this possible? If one file assigned to an ID...
I have a page that lists property listings assigned to a specific user (a manage page), with brief t

I have a parse error in this query help..
Code: $query1="INSERT INTO `rating` (`item_name`, `rating`, `ip_address`, `date_rated`) VALUES

Best way to check for end of a record and send it back to the first record
I'm hoping someone can help me out and explain the best way to accomplish this.

What I'm doin

Do something every fifth time?
I'm trying to write a loop, but I want it to do something different after every fifth instance. Like

uploading video files into mysql in php
hi,
I have the video files which i have to upload into mysql db. along with creating thumbnails f

need to apply an if/else statement to Tim Thumb script
Not sure how to work this. I essentially want to call a variety of image sizes based on which style

Not adding to db
Hi, I can't figure out why it won't add the record to the database. It's just a simple form to get

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash