Can't seem to capture a variable in a chained select

Posted on 16th Feb 2014 07:03 pm by admin

I'm *this* close to having a chained select running but for some reason it doesn't seem to be picking up a variable.

Code: <?php

require ('inc/connection.php');

//seeming that we are just submitting and refreshing to the one page we need to check if the post variable is set, and if so a couple of other variables are set
if(!isset($_POST['state'])) {
$next_dropdown = 0;
}
else {
//When set this variable reveals the next drop down menu
$next_dropdown = 1;
//this variable keeps the previous selection selected
$selected = $_POST['state'];
}
?>

<form name="form" method="post" action="">
<select name="state" style="font-size:20px;">
<option value="NULL">State</option>
<?php
$query = "SELECT id, name FROM state ORDER BY name ASC";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{?>
<option value="<?php echo $row[0]; ?>" onClick="document.form.submit()" <?php if(isset($selected) && $row[0] == $selected) {echo "selected='selected'";} ?>><?php echo $row[1]; ?></option>n";
<?php }
echo '</form>n';
//this is where the other form will appear if the previous form is submitted
if($next_dropdown == 1) {?>
<form name="form2" action="" method="post">
<select name="city">
<option value="NULL">City</option>
<?php
$query2 = "SELECT * FROM city WHERE state_id = " . $row[0];
$result2 = mysql_query($query2);
while($row2 = mysql_fetch_array($result2))
{ ?>
<option value="<?php echo $row2[0]; ?>" onClick="document.form2.submit()"><?php echo $row2[1]; ?></option>
<?php }?>
</select>
</form>
<?php }
?>

The state drop down works fine. Once a state is selected, it will display the city drop down. However, the city drop down never populates. It's as though it forgets what $row[0] is. Any thoughts?

Your Answer:

Login to answer

Other forums

Attempt to assign property of non-object in...
I'm having issues with the following function in PHP 5...

function getTreeWithChildre

PHP Include w/If IE Condition Statement?
I was having a problem with Internet Exploder (big surprise, right?) displaying my drop down menus i

mysql query with single quotes in a variable
$sitedetails = "INSERT INTO vars (address, sitename, description, ownername, theme) VALUES ('$u

Date Format
Hi there,

I have a date format like this right now:
Sat, 17 Oct 2009 17:04:00

I ne

please help
HTML Code:

Code: <span id="ctl00"><span>

Internal class functions don't seem to get executed.
Hi. Can someone please put me out of my misery on this. I don't write much PHP and this has me baffl

Multiple forms on the same page (safari)
Hello everyone,

I have 3 forms on the same page, that opens in a new window and submits to a

removing space from the end of a variable
i have a variable $image which contains the following url "http://tiles.xbox.com/tiles/oo/P5/0m

Renaming a file that a user uploads to site?
My site allows for registered users to upload images to the site under their own gallery. Currently

Allowing ' and "
Hello everyone,

I am creating a form where users submit information to go into a database. I