Can't seem to capture a variable in a chained select


Posted on 16th Feb 2014 07:03 pm by admin

I'm *this* close to having a chained select running but for some reason it doesn't seem to be picking up a variable.

Code: <?php

Did you know?Explore Trending and Topic pages for more stories like this.
require ('inc/connection.php');

//seeming that we are just submitting and refreshing to the one page we need to check if the post variable is set, and if so a couple of other variables are set
if(!isset($_POST['state'])) {
$next_dropdown = 0;
}
else {
//When set this variable reveals the next drop down menu
$next_dropdown = 1;
//this variable keeps the previous selection selected
$selected = $_POST['state'];
}
?>

<form name="form" method="post" action="">
<select name="state" style="font-size:20px;">
<option value="NULL">State</option>
<?php
$query = "SELECT id, name FROM state ORDER BY name ASC";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{?>
<option value="<?php echo $row[0]; ?>" onClick="document.form.submit()" <?php if(isset($selected) && $row[0] == $selected) {echo "selected='selected'";} ?>><?php echo $row[1]; ?></option>n";
<?php }
echo '</form>n';
//this is where the other form will appear if the previous form is submitted
if($next_dropdown == 1) {?>
<form name="form2" action="" method="post">
<select name="city">
<option value="NULL">City</option>
<?php
$query2 = "SELECT * FROM city WHERE state_id = " . $row[0];
$result2 = mysql_query($query2);
while($row2 = mysql_fetch_array($result2))
{ ?>
<option value="<?php echo $row2[0]; ?>" onClick="document.form2.submit()"><?php echo $row2[1]; ?></option>
<?php }?>
</select>
</form>
<?php }
?>

The state drop down works fine. Once a state is selected, it will display the city drop down. However, the city drop down never populates. It's as though it forgets what $row[0] is. Any thoughts?
No comments posted yet

Your Answer:

Login to answer
83 Like 35 Dislike
Previous forums Next forums
Other forums

Line break?
Hi, I'm new to the forum and new to php. I'm not sure if I'm using the correct terminology so here i

Custom array sort? asc then desc
Any ideas how I could sort this array? I've been trying for a while. Maybe with usort, but I have no

PL/SQL: ORA-00947: not enough values error message
Hi all i am getting Error(25,63): PL/SQL: ORA-00947: not enough values error message when executing

Help with parsing this html
Hi,
I've got some html i just need a couple of strings from.. argh, it's freaking me out. I've t

noob cURL help
I have a pretty basic form that I need to cURL post to a file in my includes folder (includes/login.

Keeping data in form
How can I keep whatever I write in the form?

$_POST variable un-useable
I'm trying to use a $_POST variable in a mysql update statement but i can't use it for some unknown

Filtering for a phrase using pregmatch
Here is my code which looks for addresses which start with ' src=" '

Code: [Select]preg_

Table control is disappearing from Screen
Hi Experts,

I have a screen with multiple table control(TC). Each table control has two c

strtotime issue
Hey all,

I'm playing around with some code, and basically the idea is:

Person changes

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash