Can't seem to capture a variable in a chained select


Posted on 16th Feb 2014 07:03 pm by admin

I'm *this* close to having a chained select running but for some reason it doesn't seem to be picking up a variable.

Code: <?php

Did you know?Explore Trending and Topic pages for more stories like this.
require ('inc/connection.php');

//seeming that we are just submitting and refreshing to the one page we need to check if the post variable is set, and if so a couple of other variables are set
if(!isset($_POST['state'])) {
$next_dropdown = 0;
}
else {
//When set this variable reveals the next drop down menu
$next_dropdown = 1;
//this variable keeps the previous selection selected
$selected = $_POST['state'];
}
?>

<form name="form" method="post" action="">
<select name="state" style="font-size:20px;">
<option value="NULL">State</option>
<?php
$query = "SELECT id, name FROM state ORDER BY name ASC";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{?>
<option value="<?php echo $row[0]; ?>" onClick="document.form.submit()" <?php if(isset($selected) && $row[0] == $selected) {echo "selected='selected'";} ?>><?php echo $row[1]; ?></option>n";
<?php }
echo '</form>n';
//this is where the other form will appear if the previous form is submitted
if($next_dropdown == 1) {?>
<form name="form2" action="" method="post">
<select name="city">
<option value="NULL">City</option>
<?php
$query2 = "SELECT * FROM city WHERE state_id = " . $row[0];
$result2 = mysql_query($query2);
while($row2 = mysql_fetch_array($result2))
{ ?>
<option value="<?php echo $row2[0]; ?>" onClick="document.form2.submit()"><?php echo $row2[1]; ?></option>
<?php }?>
</select>
</form>
<?php }
?>

The state drop down works fine. Once a state is selected, it will display the city drop down. However, the city drop down never populates. It's as though it forgets what $row[0] is. Any thoughts?
No comments posted yet

Your Answer:

Login to answer
83 Like 35 Dislike
Previous forums Next forums
Other forums

php is not recognized as an internal or external command
Hello,

I am trying to bake the code in CakePHP through my console.
I have changed my Path

Why does my php page download images over and over
Can anybody please explain to me why my php page keeps downloading the images and other items every

MASS PM
Hello all, I'm trying to send mass private messages to users in my database but keep getting an erro

Multiple upload and Resize
I would like some help on my script I have the for my index.php

////

<html&

Sub-domains & calling unique content
Hello,

Is there a way use something similar to the $_GET function for a sub-domain? I to be a

PHP page is blank
Hi Everyone,

I have a site in which I am able to open the first PHP webpage in my browser but

How to get the previous months last date....
Here's my wittle problem. I suck at working with dates.

So today is 10/20/2009, i need to fig

login box shows up again after logging in 2nd login works
Hello,

I am having trouble on my site Lockerz.rack111.com where when you login the login box

SQL query not working well
Hi,
I made a small table with 5 rows and want to make them an sql consult using rownum

How to show next and prev records
Hi all,

Sorry if this is simple, i'm very new to php, well, any programming language actually

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash