Getting Resource id #11 while trying to connect..

Posted on 16th Feb 2014 07:03 pm by admin

So i tried using "DEFINE" for the first time and im using the variables i defined to connect but it reports back this error:

QuoteWarning: mysql_query(): 11 is not a valid MySQL-Link resource in /home/content/p/p/f/ppffffpp/html/avalancheatblue.com/nc-cms/system/modules/storage/mysql.php on line 25
Can anyone look at the function and find out why this is?

Code: (php) [Select]<?php

function nc_save_content ($name, $data)
{

$nc_db_link = mysql_connect(NC_DB_HOST, NC_DB_USER, NC_DB_PASSWORD);
$nc_db_link = nc_db_link($nc_db_link, NC_DB_DATABASE);

$x=3;
while($x != 0){
nc_check_content($name.$x, "Edit Me History" . $x);//line 9-14 making sure the history exists (if not creates it)[function is internal]
$x--;
}

//Now start backwards and work from 2-0 moving files for history
$x=2;
$z=1;
while($x != 0){
$temp2 = $name.$x;
$get = "SELECT content FROM " .NC_DB_PREFIX."content WHERE name ='".$temp2."'";
$res = mysql_query($get,$nc_db_link) or die (mysql_error());
$row = mysql_fetch_assoc($res);

$temp = $x + 1;
$insert = "UPDATE ".NC_DB_PREFIX."content SET content='".$row['content']."' WHERE name='".$name.$temp."'";
$res2 = mysql_query($insert,$nc_db_link) or die (mysql_error());
$x--;
}

//one last thing move the current entry to 1 before we overwrite it!!!
$sql = mysql_query("SELECT content FROM " .NC_DB_PREFIX."content WHERE name ='".$name."'",$nc_db_link) or die (mysql_error());
$row = mysql_fetch_assoc($sql);

$insert = mysql_query ("UPDATE ".NC_DB_PREFIX."content SET content='".$row['content']."' WHERE name='".$name."1"."'",$nc_db_link) or die (mysql_error());



nc_check_content ($name, "Edit Me!"); // Make sure database entry exists
$nc_db_result = mysql_query("UPDATE ".NC_DB_PREFIX."content SET content='".nc_db_escape($data)."' WHERE name='".$name."'", $nc_db_link);

if(!$nc_db_result) // Check for query errors
{
nc_report_error("MySQL reported: ".mysql_error());
exit();
}

mysql_close($nc_db_link); // Close connection
}
?>

Your Answer:

Login to answer

Other forums

Problem with Sending Mail by PHP
hello all,
I m new to php, can u plz provide me the code to send mail by php having CAPTC

PHP Array quick help
I need

$_SESSION{'username'} to be like this:


if $_SESSION['username'] = "gay

Allowing ' and "
Hello everyone,

I am creating a form where users submit information to go into a database. I

Supress some serveroutput but not all
Hi,

I have a script I'm working on that uses plsql to create and RMAN script, this uses d

Drop Down and text box issue
Is it possible to set a drop down list and text boxes to a certain width?

here is my code

Displaying image pathname instead of image
Hello

Im trying to upload and then display images from a mysql database - Its only basic and

Hyperlink in PHP to MySQL record
Hello,

I am having trouble as i am new to php. I have connected to the database and I have di

Select Lists into MYSQL
Hello All, I am new to PHP @ 1 week. So borrowing code anywhere I can. I am making progress, but h

Protecting forms
Alright, I want to protect some forms of mine from SQL Injections, because I had someone earlier spa

need help in php variable
i have a php variable on one page
Code: [Select]$lastId = mysql_insert_id($db);
echo $lastId;<