Most basic form question ever?

Posted on 16th Feb 2014 07:03 pm by admin

Hello,

I want to use this snippet to make sure the fields in a form are ok before processing it.

Code: <FORM method="post">
To:


<input type="text" name="name" size="40" value="<?php if($name) { print $name; } else { print "Insert Name"; } ?>">

<input name="action" type="submit" value="Update Form">

</FORM>

It works, but I don't understand why.

The if statement is checking for the variable $name, but I haven't used the code that I would normally use.

What I see in all my tutorials would lead me to use...

$name= $_POST['name];

So, I'm confused as to where the $name variable is being found.

Thanks for your patience

Your Answer:

Login to answer

Other forums

Oracle Connectivity
Hi Every One,

Can we access SAP from oracle database.If it possible then please spec

PHP XML extraction text
I would like to extract an xml text and have that text directly echo(print) out on my web page. Her

Generating unique numbers using php
Hi,
I need help in generating unique number using php.I tired using rand() in php.But, by using r

Not reloading page after php form submit
Hello helpful souls out there. You guys have come through for me in the recent past and I'm hoping s

Loop Through Date Range
Hi guys,
I have date range as parameter like 01/JAN/2009 TO 16/JAN/2009 now i want to loop thro

How to read CSS message data
Hi,
I have a requirement here. When working as a Dev angel for multiple customers its really di

When file included, REMOTE_ADDR is server's?
I have an index file that handles my site, basically index.php?page=ip will activate "require('

CODE NOT WORKING
Code: [Select]<?php
//include shared codes

include '../lib/common.php';
include

Fetching array then reversing it
Hi, I have a simple problem, I'll try to explain it as best I can:
News entries in my database ar

Structure Question - One Table or One Table Per Record Set?
I have a web app (mySQL and PHP) which allows people to create an item with up to 200 records which