Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
what is wrong with this
Code: [Select]<?php
if ($_SERVER['HTTP_REFERER'])
{
Please help - should be a simple fix.. driving me nuts
Everything seemed to be working fine. I have a table, it alphabetically lists a bunch of cities and
Extending Exception to contain method name
I was wondering, if there's a way to extend Exception in such a way, that it would contain name of a
check comment for html
hi, I just wanted to check if a comment a user posts contains HTML, and if it does, to not allow it
What do you call the "token" thing?
You know how some sites have links that run on tokens? Tokens are links that only stay alive for a c
How do I give a developer access to a specific directory and nothing else?
I want to give a develop access to a specific directory and nothing else
I can give them an F
ALV List Display to point to another report on Double Click
Hi,
I want my ALV List Display to point to another report on Double Click on its line ite
Parse error: syntax error, unexpected $end in
hello,
i receive the error :Parse error: syntax error, unexpected $end in C:xamppxampphtdocsh
Cache PHP Objects/Classes?
Does anyone have ideas about caching PHP objects using something like: http://memcached.org/
Server side $_SESSION
how does one keep the session completely server side. no cookies to the browser at all. i need this
