PHP page loading in Firefox but not in IE


Posted on 16th Feb 2014 07:03 pm by admin

hello,

i am currently doing a project in PHP and i have a problem. If I view the project in Mozilla Firefox it works fine but if i open using IE i am having problem with the design which is not getting displayed(i.e the banner is not getting displayed but the page footer is getting displayed.) Between the two, there is a grid which is also getting displayed in both the browsers.You can check it out at http://ems.acuraits.com/logauth.php. Please help me at the earliest.

Did you know?Explore Trending and Topic pages for more stories like this.
Eagerly waiting for your reply.
No comments posted yet

Your Answer:

Login to answer
160 Like 12 Dislike
Previous forums Next forums
Other forums

Why do I get this error?
Error:

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or

Passing an array of values From VB6.0 to Oracle PL/SQL Function
Basically we are using VB6.0.

When we try to pass an array from VB6.0 to an Oracle PL/SQL

Insert numbers from Barcode scanner into online php page
I have a real big problem, Here is what I'm trying to do. I have a Intermec CN3 handheld computer th

Loop Through Date Range
Hi guys,
I have date range as parameter like 01/JAN/2009 TO 16/JAN/2009 now i want to loop thro

my sql select id and then update problem.
I need to select some auto incremented ids out of a database and then use those id in a where statem

Creating an invoice
Using fpdf I am trying to create an invoice to send to clients. The products are sold in pricing tie

Looking for help on using joining mysql tables and php....
Does anyone have any good links to references on how to pull mysql data, through joining tables and

Help Ordering Arrays
Hi, I have 3 arrays as shown below.

Code: $users = $this->get_latest_users();
$flir

Hotlinking Picasa as the image folder of a website
Hi there PHP freaks, I would like to create a private album in Picasa to use it as the image folder

$action = "insert"; //$action = $_GET['action'];
$action = "insert";
//$action = $_GET['action'];

why is this invalid type? I am

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash